20x^2-128x/21=4

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Solution for 20x^2-128x/21=4 equation: 


x in (-oo:+oo)

20*x^2-((128*x)/21) = 4 // - 4

20*x^2-((128*x)/21)-4 = 0

20*x^2+(-128/21)*x-4 = 0

20*x^2-128/21*x-4 = 0

DELTA = (-128/21)^2-(-4*4*20)

DELTA = 157504/441

DELTA > 0

x = ((157504/441)^(1/2)+128/21)/(2*20) or x = (128/21-(157504/441)^(1/2))/(2*20)

x = ((157504/441)^(1/2)+128/21)/40 or x = (128/21-(157504/441)^(1/2))/40

x in { (128/21-(157504/441)^(1/2))/40, ((157504/441)^(1/2)+128/21)/40 }

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